Angle D is 180° -75° -45° = 60°. Drawing altitude MX to segment DN divides the triangle into ΔMDX, a 30°-60°-90° triangle, and ΔMNX, a 45°-45°-90° triangle. We know the side ratios of such triangles (shortest-to-longest) are ...
... 30-60-90: 1 : √3 : 2
... 45-45-90: 1 : 1 : √2
The long side of ΔMDX is 10√3, so the other two sides are
... MX = MD(√3/2) = 15
... DX = MD(1/2) = 5√3
The short side of ΔMNX is MX = 15, so the other two sides are
... NX = MX(1) = 15
... MN = MX(√2) = 15√2
Then the perimeter of ΔDMN is ...
... P = DM + MN + NX + XD
... P = 10√3 +15√2 + 15 + 5√3
... P = 15√3 +15√2 +15 . . . . perimeter of ΔDMN
Answer:
49π sq. units
Step-by-step explanation:
Find the diagram attached
We can find the area of the given circle
Given
diameter of the circle d = 14
Area of the circle = πd²/4
Substitute the given diameter
Area of the circle = π(14)²/4
Area of the circle = 196π/4
Area of the circle = 49π sq. units
Hence the exact answer in terms of π is 49π sq. units
Answer:
6
Step-by-step explanation:
Okay so the shape has an area of 60 square inches. The formula for the area of a triangle is A = b*h where A = area, b = base, and h = height
So we are given the value for A (60)
We are given the value for height (10)
So we just need to find the value of the base
So let's set this up as an equation. Input the given values into the area for triangle formula
A = B*h
60 = B * 10
So we need to solve for B. To do that we need to get B alone on one side of the = sign. B is being multiplied by 10 so do the opposite and divide both sides by 10
60 divided by 10 = 6
10 divided by 10 = 1 (don't actually put a 1 down, just drop it)
So we are left with
6 = B
So the base is 6 square inches. To test, put it in the equation:
A = B*h
60 = 6*10
60 = 60
Answer:
a.
the area of each parallelogram
<em>a. 66</em>
<em>b. 49</em>
<em>c. 25</em>
<em>d. 32</em>
<em>e. 18</em>
Step-by-step explanation:
a parallelogram is similar to a rectangle when you are finding the ares, you use the base and the height to find the area. If it helps, like the text suggested, just change them to look like a rectangle and then find the area.
