Answer:
∠PQS= 3(x +5)
Step-by-step explanation:
∠PQR = 5x + 25
∠SQR+∠PQS= 5x+25
∠PQS = ∠PQR-∠SQR
∠PQS= (5x + 25 )-(2x + 10)
∠PQS = 5x+25 -2x-10
∠PQS= 3x +15
∠PQS= 3(x +5)
Here we are finding x, given the angle and adjacent side. To find x we will use the function cos as cos = a/h.
So let's do cos(35°) = 15cm / x
cos(35°) = 0.8 (1 dp)
x = 15 cm / cos(35°)
x = 18.3 cm (1 dp)

seperable differential equations will have the form

what you do from here is isolate all the y terms on one side and all the X terms on the other

just divided G(y) to both sides and multiply dx to both sides
then integrate both sides

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it
In your problem,

so all you need to integrate is
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