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aleksklad [387]
1 year ago
13

WILL RECIEVE BRANILIEST IF ANSWERED CORRECT

Mathematics
1 answer:
Klio2033 [76]1 year ago
4 0

Answer:

B

Step-by-step explanation:

The answer is B because we can estimate by seeing that: 3 x 3 = 9, so henceforth the answer must be between 3 and 4, so it must be B.

You might be interested in
Simplify the expression, only odds 9-17
Elodia [21]

All exercises involve the same concept, so I'll show you how to do the first, then you can apply the exact same logic to all the others.

The first thing you need to know is that, when a certain quantity multiplies a parenthesis, you can distribute that number to every element in the parenthesis. This means that

a(b+c) = ab+ac

So, a is multiplying the parenthesis involving b and c, and we distributed it: a multiplies both  b and c in the final result.

Secondly, you have to know how to recognize like terms, because they are the only terms you can sum. Two terms can be summed if they have the same literal expression. So, for example, you cannot sum 3x+2y, and neither 5x^2-4x exponents count.

But you can su, for example,

5x-3x = (5-3)x = 2x

or

23xy^2z^6 - 17xy^2z^6 = 6xy^2z^6

So, take for example exercise 9:

1.2(7x-5y) - (10y-4.3x)

We distribute the 1.2 through the first parenthesis:

1.2(7x-5y) = 1.2 \cdot 7x - 1.2 \cdot 5y = 8.4x-6y

And you can distribute the negative sign through the second parenthesis (it counts as a -1 to distribute):

- (10y-4.3x) = -10y+4.3x

So, the expression becomes

8.4x-6y-10y+4.3x

Now sum like terms:

(8.4+4.3)x + (-6-10)y = 12.7x - 16y

7 0
3 years ago
Tampa Bay Buccaneers Super Bowl Contenders?
mafiozo [28]

Answer:

Australia.

Bangladesh.

England.

India.

New Zealand.

South Africa.

Sri Lanka.

West Indies.

Step-by-step explanation:

none

hope this helps

6 0
3 years ago
If outliers are discarded, then the retirement savings by residents of Econistan is normally distributed with a mean of $100,000
zavuch27 [327]

Answer:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:

X \sim N(100000,20000)  

Where \mu=100000 and \sigma=20000

We are interested on this probability

P(X>117000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

7 0
2 years ago
Steps for solving rational equations
Murrr4er [49]

Answer:

1. Find the common denominator.

2. Multiply everything by the common denominator.

3. Simplify.

4. Check the answer(s) to make sure there isn't an extraneous solution.

Step-by-step explanation:

Hope this helps!

5 0
2 years ago
Read 2 more answers
The sum of 5 consecutive odd numbers is 145 what is the third number in this sequence ​
lawyer [7]

9514 1404 393

Answer:

  29

Step-by-step explanation:

The third in sequence will be the middle one, the average value of all the numbers in the sequence. That average is the sum (145) divided by the number of numbers (5).

  third number = 145/5 = 29

8 0
2 years ago
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