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8_murik_8 [283]
3 years ago
5

Find all solutions (use calculator) 5sin2x+2=0

Mathematics
1 answer:
Artemon [7]3 years ago
8 0
X = 2.93583423 + πn, 4.9181474 + πn
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Solve for x, y=3x^2 -x+1​
galben [10]
A: 5x-1=y
(=) x=(y+1)/5
7 0
3 years ago
Among cases of heart pacemaker malfunctions, were found to be caused by firmware, which is software programmed into the device.
alex41 [277]

Complete question is;

Among 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware, which is software programmed into the device. If the firmware is tested in three different pacemakers randomly selected from this batch of 8834 and the entire batch is accepted if there are no failures, what is the probability that the firmware in the entire batch will be accepted? Is this procedure likely to result in the entire batch being accepted?

Answer:

P(All three are not caused by firmware) = 83.84%

Probability that the entire batch will be accepted = 0.8384

Step-by-step explanation:

We are told that out of the 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware.

Thus,

Cases not caused by firmware = 8834 - 504 = 8330

So, probability of the first case not being affected by firmware is;

P(first case not caused by firmware) = 8330/8834

Also,

Probability of second case not being affected by firmware is given as;

P(second case not caused by firmware|first case not affected by firmware) = 8329/8833

Similarly,

Probability of third case not being affected by firmware is given as;

P(third case not caused by firmware|first and second not caused by firmware) = 8328/8832

Now, looking at the 3 Probabilities gotten, it is obvious that the events are not independent because the probability of occurence of one event depends on the probability of occurence of the other event.

Thus, we will make use of the general multiplication rule which is;

P(A & B) = P(B) × P(A|B)

Thus;

P(All three not caused by firmware) = P(first case not caused by firmware) × P(second case not caused by firmware|first case not affected by firmware) × P(third case not caused by firmware|first and second not caused by firmware)

Plugging in the relevant values, we have;

P(All three not caused by firmware) = (8330/8834) × (8329/8833) × (8328/8832)

P(All three are not caused by firmware) = 0.83840506679 ≈ 83.84%

6 0
3 years ago
The growth of a city is described by the population functionwhereis the initial population of the city, t is the time in years,
mamaluj [8]

Complete question:

The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at

Answer:

27,800

Step-by-step explanation:

We need to obtain the initial population(P0) and constant value (k)

Population function : p(t) = P0e^kt

At t = 0, population = 19,000

19,000 = P0e^(k*0)

19,000 = P0 * e^0

19000 = P0 * 1

19000 = P0

Hence, initial population = 19,000

At t = 3; population = 23,000

23,000 = 19000e^(k*3)

23000 = 19000 * e^3k

e^3k = 23000/ 19000

e^3k = 1.2105263

Take the ln

3k = ln(1.2105263)

k = 0.1910552 / 3

k = 0.0636850

At t = 6

p(t) = P0e^kt

p(6) = 19000 * e^(0.0636850 * 6)

P(6) = 19000 * e^0.3821104

P(6) = 19000 * 1.4653739

P(6) = 27842.104

27,800 ( nearest whole number)

3 0
3 years ago
What is the dilation for the transformation below?​
lys-0071 [83]

Answer:

The dialation is of 2

Step-by-step explanation:

QR = 3 units

QS = 2 units

RS = 2 units

Q'R' = 6 units

Q'S' = 4 units

R'S' = 4 units

So as you can see, this triangle has doubled it's size, since it has been multiplied by 2.

Hope this helped!

Have a supercalifragilisticexpialidocious day!

4 0
3 years ago
Solve this equation: 4+k=11
Law Incorporation [45]

Answer:

k=7

Step-by-step explanation:

4+k=11

subtract 4 from both sides to isolate k

k= 7

3 0
3 years ago
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