What type of polynomial is this
1 answer:
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Answer:
A'(-2, 1), B'(1, 0), C'(-1, 0)
Step-by-step explanation:
Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.
If a point X(x, y) is translated a units right and b units down, the new location is X'(x + a, y + b) whereas if a point X(x, y) is translated a units left and b units up, the new location is X'(x - a, y - b).
If a point X(x, y) is rotated 90° clockwise about the origin, the new location is X'(y, -x)
From the image attached, ∆ABC is at A(0, 0), B(1,3) C(1, 1)
If ∆ABC is translated 2 units down and 1 unit to the left (x - 1, y - 2), the vertices would be A*(-1, -2), B*(0, 1), C*(0, -1)
If it is then rotated 90° clockwise about the origin, the new location is A'(-2, 1), B'(1, 0), C'(-1, 0)
Answer:
The relation is explained below.
Step-by-step explanation:
P(x, y) is a point on the circle. Q is the origin. Join PQ.
PQ is the radius.
Therefore, PQ = r
Draw PS perpendicular to the x-axis.
Now, ΔPQS is a right triangle.
By Pythagoros theorem,
