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quester [9]
3 years ago
5

BAC can be proved congruent to DEF by

Mathematics
2 answers:
pychu [463]3 years ago
7 0

Answer:

ASA

Step-by-step explanation:

The right triangle cannot be A$S or AAA, SSA is incorrect.

Strike441 [17]3 years ago
3 0

Answer:

ASA

Step-by-step explanation:

∠ABC ≅ ∠EDF  Angle

BC ≅ DF            Side

∠C ≅ ∠F            Angle

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Look up online "equation calculator" and it should be the first one to appear, "Symbolab" supper easy way to help you with problems!
3 0
4 years ago
1. Solve for y in the figure below.<br> X<br> 6<br> 8<br> 8
vichka [17]
there’s nothing there srry
4 0
3 years ago
Find the value of 7v-6 given that -8v-9=7 Simplify your answer as much as possible 7v-6=
evablogger [386]

Answer:

-20

Step-by-step explanation:

-8v-9=7

Add 9 to each side

-8v-9+9=7+9

-8v = 16

Divide by -8

-8v /-8 = 16/-8

v = -2

Now find

7v -6

7(-2) -6

-14 -6

-20

4 0
4 years ago
Read 2 more answers
Integrate the following:<br><img src="https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Cint%20%5C%3A%20%20%5Ctan%28x%29%20%20%20%5
Korvikt [17]

Answer:

\huge \boxed{\red{ \boxed{  -  \cos(x)  + C}}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • integration
  • PEMDAS
<h3>tips and formulas:</h3>
  • \tan( \theta)  =  \dfrac{ \sin( \theta) }{ \cos( \theta) }
  • \sf \displaystyle \int  \sin(x)   \: dx =    - \cos(x)  +   C
<h3>let's solve:</h3>
  1. \sf \: rewrite \:  \tan( \theta)  \:  as \:   \dfrac{ \sin( \theta) }{ \cos( \theta) }  :  \\   =  \displaystyle  \int \:  \frac{ \sin(x) }{ \cos(x) }  \cos(x)  \: dx \\   = \displaystyle \int \:  \frac{ \sin(x) }{ \cancel{\cos(x) }}   \: \cancel{ \cos(x)}  \: dx \\     = \displaystyle \int \:  \sin(x)   \: dx
  2. \sf \: use \: the \: formula : \\   \sf \displaystyle     - \cos(x)
  3. \sf add \: constant :  \\   -  \cos(x)  + C

\text{And we are done!}

6 0
3 years ago
Read 2 more answers
Integrate t sec^2 (2t) dt
Neporo4naja [7]
F = t ⇨ df = dt 
dg = sec² 2t dt ⇨ g = (1/2) tan 2t 
⇔ 
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt 
u = 2t ⇨ du = 2 dt 

As integral of tan u = - ln (cos (u)), you get : 

integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant 
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant 
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer 
8 0
4 years ago
Read 2 more answers
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