Use photo math it works very well!
U = ( -8 , -8)
v = (-1 , 2 )
<span>the magnitude of vector projection of u onto v =
</span><span>dot product of u and v over the magnitude of v = (u . v )/ ll v ll
</span>
<span>ll v ll = √(-1² + 2²) = √5
</span>
u . v = ( -8 , -8) . ( -1 , 2) = -8*-1+2*-8 = -8
∴ <span>(u . v )/ ll v ll = -8/√5</span>
∴ the vector projection of u onto v = [(u . v )/ ll v ll] * [<span>v/ ll v ll]
</span>
<span> = [-8/√5] * (-1,2)/√5 = ( 8/5 , -16/5 )
</span>
The other orthogonal component = u - ( 8/5 , -16/5 )
= (-8 , -8 ) - <span> ( 8/5 , -16/5 ) = (-48/5 , -24/5 )
</span>
So, u <span>as a sum of two orthogonal vectors will be
</span>
u = ( 8/5 , -16/5 ) + <span>(-48/5 , -24/5 )</span>
The correct answer is: C.5z
Further explanation:
A factor is a number that is multiplied with a number
Let us look at the options one by one
<u>A. z+5</u>
5 is not a factor as it is being added to z.
<u>B. z-5</u>
5 is not a factor as it is being subtracted from z.
<u>C.5z</u>
5 is a factor as it is being multiplied with the z and can be separated easily
Hence,
The correct answer is: C.5z
Keywords: Factors, Multiple Choice
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Answer:10
Step-by-step explanation:
Use the distance formula to determine the distance between two points.
the answer will be 10
Based on the populations of the town from 2000 to 2008, the average rate of change of the population between 2002 and 2004 is -6.1%
The average rate of change between 2002 and 2006 is -4.88%
<h3>What is the average rate of change?</h3>
The average rate of change can be found as:
=Change in population / Population in base year
The average rate of change in population between 2002 and 2004 is:
= (77 - 82) / 82
= -6.1%
The average rate of change in population between 2002 and 2006 is:
= (78 - 82) / 82
= -4.88%
Find out more on the average rate of change at brainly.com/question/23434598
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