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3 years ago

The figure below shows two pair of congruent triangles. ΔFDE≅ _____. ΔYXW ΔXYW ΔWYX ΔWXY

Mathematics

2 answers:

Kryger [21]3 years ago

6 0

Answer:

WYX

Step-by-step explanation:

mariarad [96]3 years ago

5 0

Answer:

wxy

Step-by-step explanation:bc it is

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A shipping carton in the shape of a rectangular prism has a volume of 756 cubic inches the base area of the shipping carton is 4

coldgirl [10]

The answer would be a height o 18 inches. how you figure that is by taking the total cubic inches and divide by the base number which is 42 inches. 756 divided by 42 is 18. and to check your answer multiply. 18 times 42 equals 756.

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3 years ago

Read 2 more answers

Two runners, same time. Alan travels east at a uniform rate that is 2 mph faster than ed, who is traveling west. After two hours

True [87]

Ed is going 12 miles per hour.

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3 years ago

Paige launched a ball using a catapult she built. The height of the ball (in meters above the ground) ttt seconds after launch i

agasfer [191]

Answer:

1) Factor form : $h(t)=-5t(t-8)$

2) 8 second after launch.

Step-by-step explanation:

The height of the ball (in meters above the ground) t seconds after launch is modeled by

$h(t)=-5t^2+40t$

To find the time when ball hit the ground, we need to find the factor form of the given function.

$h(t)=-5t(t-8)$

When ball hi the ground, then height of the ball from the ground is 0.

$h(t)=0$

$-5t(t-8)=0$

Using zero product property, we get

$-5t=0\Rightarrow t=0$

$t-8=0\Rightarrow t=8$

Ball hit the ground at t=0 and t=8. It means ball hit the ground in starting and 8 second after launch.

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3 years ago

Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

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3 years ago

R= 0.75s for s solving for a variable ANSWER PLEASE ASAP

Butoxors [25]

Answer:

S= 1.<u>3</u>r

Step-by-step explanation:

The 3 is underlined because it was suppose to go on top of the 3 but it didn't give me the option but that means infinity of 3

If you need more information you cant tell me hope this helped!

7 0

3 years ago