The figure below shows two pair of congruent triangles. ΔFDE≅ _____. ΔYXW ΔXYW ΔWYX ΔWXY
2 answers:
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Answer:
<em>Direction of the boat is 43.05° and the speed is 21.66 knot</em>
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Step-by-step explanation:
yacht speed = 20 knots
yacht bearing = 185° = 85° below the negative horizontal x-axis
wind speed = 15 knots
wind bearing = 290° = 20° above the negative horizontal x-axis
we find the x and y components of the boat velocities
for yacht,
x component = -20 cos 85° = -1.74 knots
y component = -20 sin 85° = -19.92 knots
for the wind,
x component = -15 cos 20° = -14.09 knots
y component = 15 sin 20° = 5.13 knots
total x component Vx = -1.74 + (-14.09) = -15.83 knots
total y component Vy = -19.92 + 5.13 = -14.79 knots
Resultant speed of the boat =
==> = <em>21.66 knot</em>
<em></em>
direction of boat =
==> = <em>43.05°</em>
Answer:
Step-by-step explanation:
Given expression is:
First we will use the rule:
So for the given expression:
We will use tha property of multiplication on powers:
Applying the outer exponent now