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3 years ago

Hard question need help My mom is mad please help Middle school will like and give brainliest

Mathematics

1 answer:

LekaFEV [45]3 years ago

3 0

Isiah, you have been to careless to cut out your tabs on your computer. Now a stranger knows you go to Belmont Ridge Middle School in Loudon Virginia.
Please learn about internet safety with an adult because stuff like this can be dangerous

You might be interested in

What the slope of a line

swat32

Answer:

The slope of a line is a number that measures its "steepness", usually denoted by the letter m. It is the change in y for a unit change in x along the line.

Hope it helps.

5 0

3 years ago

10 more than 2 times a number is equal to 2 times the number plus 50. What is the number?

PSYCHO15rus [73]

Answer:

y = 40 is the answer

Step-by-step explanation:

Let the number be y

10 more than 2 times a number = 10 + 2×y

equal to 2 times the number plus 50. = 2 × y + 50

10 + 2y = 2y + 50

combine the like terms

2y - 2y =50 - 10

0 = 40

the number supposes be 40 but the number is represented by 0

i think some thing is missing in your question

y supposes be 40 not 0 = 40

Hope this helps!

3 0

3 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$