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STatiana [176]
2 years ago
9

If y varies directly with x, find the value of y when x = 27 for the direct variation with the given information. y = 7 when x =

-9 y =​
Mathematics
1 answer:
ElenaW [278]2 years ago
3 0

Given:

y varies directly with x,

It is given that y = 7 when x = -9.

To find:

The value of y when x = 27 for the direct variation.

Solution:

It is given that y varies directly with x, so

y\propto x

y=kx             ...(i)

Where, k is the constant of proportionality.

It is given that y = 7 when x = -9. Putting these values in (i), we get

7=k(-9)

-\dfrac{7}{9}=k

Putting k=-\dfrac{7}{9} in (i), we get

y=-\dfrac{7}{9}x

Putting x=27,  we get

y=-\dfrac{7}{9}(27)

y=-21

Therefore, the required value is y=-21.

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a random sample of 510 high school students has a normal distribution. The sample mean average ACT exam score was 21 with a 3.2
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Answer:

CI = 21 ± 0.365

Step-by-step explanation:

The confidence interval is:

CI = x ± SE * CV

where x is the sample mean, SE is the standard error, and CV is the critical value (either t score or z score).

Here, x = 21.

The standard error for a sample mean is:

SE = σ / √n

SE = 3.2 / √510

SE = 0.142

The critical value is looked up in a table or found with a calculator.  But first, we must find the alpha level and the critical probability.

α = 1 - 0.99 = 0.01

p* = 1 - (α/2) = 1 - (0.01/2) = 0.995

Using a calculator or a z-score table:

P(x<z) = 0.995

z = 2.576

Therefore:

CI = 21 ± 0.142 × 2.576

CI = 21 ± 0.365

Round as needed.

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Kenji is decorating papers with a total of 15 heart stickers and 12 star stickers for the child he is babysitting. If he wants t
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