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grandymaker [24]
3 years ago
10

Can a real person help me out all the hackers just want me to delete the app

Mathematics
1 answer:
klasskru [66]3 years ago
5 0

Answer:

Question 7: <em>x</em> = 36

Question 4: <em>x</em> = 14

Question 9: D

Step-by-step explanation:

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Help me please pretty plese
noname [10]
The answer would be 9
4 0
3 years ago
Read 2 more answers
What is the simplest form of 7/10 + 1/5
earnstyle [38]
Solutions 

1) Find the least common denominator of 7/10 and 1/5. 
10: 10 
5 : 5 , 10 
The least common denominator is 10. 

2) Make the denominator of 1/5 to 10. Multiply numerator and denominator by 2.

1 x 2 = 2 
5 x 2 = 10

3) New fraction 
7/10 + 2/10 

4) Add 
7+2 = 9 

9/10 is answer 

9/10 can not be simplified. It is already in reduced form. 
  


7 0
3 years ago
Read 2 more answers
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 6%
Georgia [21]

Answer:

a

\% E =  0.9 \%

b

\%E_1 = 10.1 \%

Step-by-step explanation:

From the question we are told that

The probability that an employees suffered lost-time accidents last year is P(e) =  0.06

The probability that an employees suffered lost-time accident during the current year is

P(c) =  0.05

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

P(c | e) =  0.15

Generally the probability that an employee will experience lost time in both year is mathematically represented as

P(c \ n \ e) =  P(e) *  P(c \ |\ e)

=> P(c \ n \ e) =  0.06*   0.15

=> P(c \ n \ e) = 0.009

Generally the percentage of employees that will experience lost time in both year is mathematically represented as

\% E =  P(e \ n \ c ) * 100

=> \% E =  0.009 * 100

=> \% E =  0.9 \%

Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

P(e \ u \ c) =  P(e) + P(c) - P(e \ n \  c)

=> P(e \ u \ c) =  0.06 + 0.05 - 0.009

=> P(e \ u \ c) =  0.101

Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

\%E_1 = P(e \ u \ c) *  100

=> \%E_1 = 0.101*  100

=> \%E_1 = 10.1 \%

7 0
3 years ago
Your friend’s heart beats 18 times in 15 seconds when at rest. While running, your friend’s heart beats 25 times in 10 seconds.
Aleks [24]
72 times at rest and 250 while running.
5 0
3 years ago
Without using calculator or table find the value of sin 15°​
lubasha [3.4K]

Answer:

.25881

Step-by-step explanation:

sin15

=sin(45-30)

=sin45.cos30-cos45.sin30

=(0.707×0.86)-(0.707×0.5)

=(0.6082)-(0.3535)

=0.25

6 0
3 years ago
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