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larisa86 [58]
3 years ago
14

Select a figure from the options which will replace the(?) as established by the problem figure ​

Mathematics
1 answer:
krok68 [10]3 years ago
4 0

Answer:

a) is the correct answer.

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Which logarithmic equation is equivalent to 2^5=32?
kolbaska11 [484]

Answer: 5=log_{2}(32)


Step-by-step explanation:

1. By definition, you have if y=b^{x}, then x=log_{b}(y)

2. Keeping this on mind, you must follow the proccedure shown below:

- You have that:

2^{5}=32

Where:

x=5\\y=32\\b=2

- Substitute values into x=log_{b}(y). Then, you obtain:

5=log_{2}(32)


6 0
3 years ago
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A line passes through the points (2,21) and (8,27). Write a linear function rule in terms of x and y for
tatiyna
We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
6 0
2 years ago
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I need answer how to do number 3
Olegator [25]
You know that you need two already to make one hexagon. So, if you multiply, or add two four times, 2+2+2+2, you would get eight.
3 0
3 years ago
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3. Six neighborhood children - Leisha, Benito, Delia, Charlotte, Weldon, and Zina- were measured
sergij07 [2.7K]
Zina, weldon, delia, leisha, bento, charlotte
8 0
3 years ago
Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando
Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

6 0
3 years ago
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