All categories

3 years ago

Here is a scatter plot:

Mathematics

1 answer:

inysia [295]3 years ago

3 0

Wait what try using photomath it helps explain and gives the answer.

You might be interested in

(143(5) + 67)5-----------Anybody???:)

Vikentia [17]

<span>(143(5) + 67)5
Multiply 143 by 5
(715 + 67)5
Add the numbers inside the parenthesis(715 and 67).
(782)5
Multiply 782 by 5.
Final Answer: 3,910</span>

6 0

3 years ago

Monique wants to bake a cake. She needs 2 1/8 cups of sugar, and 1 5/24 cups of flour. How many cups of ingredients will she use

rewona [7]

Answer:

3 1/3 cups total

Step-by-step explanation:

Add together 2 1/8 cups and 1 5/24 cups. The LCD here is 24, and so we rewrite 2 1/8 cups as 2 3/24 cups.

Adding 2 3/24 cups and 1 5/24 cups, we get 3 8/24 cups,

which simplifies to 3 1/3 cups total

5 0

3 years ago

Find the sum: 4 root 3 plus 11 root 3

ICE Princess25 [194]

Answer:

21 root is the answer I think u just add it

5 0

3 years ago

Five years ago p was 5 times older than l. In ten years l will be 4/7 as old as p. What are the current ages of l and p?

Sauron [17]

Answer: $\dfrac{110}{13},\dfrac{290}{13}$

Step-by-step explanation:

Let $a_{I}$ be the present age of I.

Let $a_{p}$ be the present age of P.

$5$ years ago P was $5$ times older than l.

Age of P $5$ years ago is $a_{p}-5$

Age of I $5$ years ago is $a_{I}-5$

$5\times (a_{I}-5)=a_{p}-5\\5a_{I}=a_{p}+20$ ....(i)

After $10$ years l will be $\frac{4}{7}$ as old as P.

Age of P $10$ years after is $a_{p}+10$

Age of I $10$ years after is $a_{I}+10$

$a_{I}+10=\frac{4}{7}\times (a_{p}+10)\\ 7a_{I}+30=4a_{p}$ ...(ii)

using (i) and (ii),

$7a_{I}+30=4(5a_{I}-20)\\110=13a_{I}\\a_{I}=\frac{110}{13}years$

$a_{P}=5a_{I}-20=5\times \frac{100}{13}-20=\frac{290}{13} years$

7 0

3 years ago

If the public debt of a country in 2009 was 12,752,000,000,000and the budget for 2010 was in deficit by $201,645,000,000, what w

LenKa [72]

The public debt was $12953645000000

7 0

4 years ago