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muminat
3 years ago
13

Point M lies between points L and N on .

Mathematics
2 answers:
Alex Ar [27]3 years ago
8 0

Answer:

LN=64 units

Step-by-step explanation:

step 1

Find the value of x

we know that

LN=LM+MN -----> equation A

see the attached figure to better understand the problem

we have

LN=12x+16

LM=10x+8

MN=5x-4

substitute the values in the equation A

12x+16=(10x+8)+(5x-4)

Solve for x

12x+16=15x+4

15x-12x=16-4

3x=12

x=4

step 2

Find the value of LN

LN=12x+16

LN=12(4)+16=64 units

seropon [69]3 years ago
4 0

Answer:

d

Step-by-step explanation:

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What is the period of y=3cot(4x−3π)
Stells [14]
Hello!

hint: we can rewrite your function as below:

<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π = 

=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)

</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

<span>"4P=π"


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4 0
3 years ago
ASAP PLEASE HELP ME
Grace [21]
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4 0
3 years ago
Rewrite the following equation in standard form.<br><br> y= -5/8x− 7
Colt1911 [192]

Answer:


Step-by-step explanation:

y= -5/8x-7

To write in standard form get all the terms to one side

y+5/8x+7=0

I hope this is correct

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6 0
3 years ago
3. Maria is a veterinarian. She wants to know how the weight of a puppy is related to its length. To find out, Maria randomly se
sweet [91]

Answer:

Part A. I chose points (7,1.3) and (48,9.8)

Part B. a. Positive correlation; b.  y = 0.21x - 0.2

Step-by-step explanation:

Part A.

I chose the first and last points on the line — (7 in, 1.3 lb) and (48 in, 9.8 lb).

That put three points on the line, three above it, and four below.

Part B

a. Type of correlation

There is a positive correlation between the length of a puppy and its weight.

You would expect a longer dog to be bigger and weigh more than a shorter dog.

b.  The equation for the line of best fit

The slope-intercept equation for a straight line is

y = mx + b

where m is the slope of the line and b is the y-intercept.

The line passes through the points (7,1.3) and (48, 9.8).

(i) Calculate the slope of the line

\begin{array}{rcl}

m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\ & = & \dfrac{9.8 - 1.3}{48-9}\\\\& = & \dfrac{8.5}{41}\\\\& = & \textbf{0.21 lb/in}\\\\\end{array}

The slope of the line is 0.21 lb/in.

(ii) Locate the y-intercept

Put the slope and the coordinates of one point into the slope-intercept formula.

\begin{array}{rcl}y & = & mx + b\\1.3 & = & 0.21\times7 + b\\1.3 & = & 1.47 + b\\b & = & -0.2\\\end{array}

The y-intercept is at (0,-0.2)

(iii) Write the equation for the line

y = 0.21x - 0.2

5 0
3 years ago
Who can solve this exercises pleaseeee i have a exam
Leona [35]

Answer:

Step-by-step explanation:

1) Two angles supplementary. So sum of two angles is 180

One angle  = x

Other angle = 2x

x + 2x = 180

3x = 180

x = 180/3 = 60

The angles are 60, 120

2)Two angles complementary. So sum of two angles is 90

one angle  = x

Other angle = x + 20

x +x +20 = 90

2x + 20 = 90

2x = 90- 20

2x = 70

x = 70/2 = 35

The angles are 35,55

3) one angle =x

Other angle = 3x - 20

x + 3x - 20 = 120

4x = 120 + 20

4x = 140

x = 140/4 = 35

The angles are 35,85

5) x + 4x -20 = 180

5x = 180 + 20

5x = 200

x = 200/5 = 40

x = 40

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4 years ago
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