x<_-4 or (-*infinity*,-4]
Step-by-step explanation:
Answer: 
Step-by-step explanation:
(3x^2+x-1)(x^4-2x+1)
=3x^6-6x^3+3x^2+x^5-2x^2+x-x^4+2x-1
=3x^6+x^5-x^4-6x^3+x^2+3x-1
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<h3>
Answer: B) 6</h3>
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Explanation:
x = original side length
2x = double the side length
The old area is x^2. The new square area is (2x)^2 = 4x^2
new area = (old area) + 27
4x^2 = x^2 + 27
4x^2-x^2 = 27
3x^2 = 27
x^2 = 27/3
x^2 = 9
x = sqrt(9)
x = 3
The old original square has a side length of 3 units.
The new larger square has a side length of 2x = 2*3 = 6 units which is the final answer (choice B)
old area = 3^2 = 9
new area = 6^2 = 36
The jump from 9 to 36 is +27 to help confirm the answer.
Answer:-5
Step-by-step explanation:
2x+7-x+12=14
x+19=14
x=-5
24 means that all the sides together equal 24 inches. Since a squares sides are all the same length you take 24 and divide it by four. this gives you 6. so the width and length of the square are both 6