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3 years ago

What is the approximate circumference of Circle C?

1 answer:

5 0

If you have the radius, then do Radius times 2 to get the diameter, then do diameter times Pi (3.14) to get the circumference
E.g. If the radius was 4, times by 2 to get the diameter so 4x2=8 then do 8x3.14 (pi) to get the circumference.

You might be interested in

Is 5/6 close to 1, 0, or 1/2. Explain

Brums [2.3K]

5/6 is closest to 1 because it it 1/6 away from 1 and is 5/6 away from 0 and is 2/6 away from 1/2 (referring 1/2 as 3/6) Hope this helps!

5 0

3 years ago

Say that a supplier claims they are 99% confident that their products will be in the interval of 50.02 to 50.38. You take sample

nydimaria [60]

Answer:

The supplier becomes less accurate than they otherwise would have tried to claim. A further explanation is below.

Step-by-step explanation:

According to the provider, this same width of that same confidence interval would be as follows:

= $50.38 - 50.02$

= $0.36$

Depending on the input observed, the width including its confidence interval would be as follows:

= $50.39 - 50.01$

= $0.38$

As even the width of that interval again for survey asserted > the width including its confidence interval according to the provider's statement, we could conclude that such is the appropriate reaction.

3 0

3 years ago

Geometry it's about relations within triangles. need help solving for variables

elena-14-01-66 [18.8K]

Answer:

`18. x=9

19. x=4

20. x=25,5

21. x=3

22. x=3,5

23. x=10

Step-by-step explanation:

5 0

2 years ago

Simplify x + 4 - 5x - 2

Blababa [14]

Answer:

-2(2x-1)

Step-by-step explanation:

x+4-5x-2

1) collect like like terms

-4x+2

2) factor out the -2

-2(2x-1)

3) that gives you the final answer of

-2(2x-1)

7 0

3 years ago

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

$P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]$

As, $P(z>1.28)=0.10$ [By z-table]

Then,

$\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712$

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0

3 years ago