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just olya [345]
2 years ago
6

The animal shelter needs to split 6 1/2 pounds of dog food equally among the 13 dogs in the facility. How much dog food will eac

h dog receive?
Mathematics
2 answers:
AveGali [126]2 years ago
3 0

Answer:

1/2 pound for each dog.

Step-by-step explanation:

Don't get confused. There are only 2 numbers which will give 2 different answers: 2 and 1/2. Which one is correct?

You want the units to be pounds per dog or pounds/ number of dogs.

The numerator is 6.5

The denominator is dogs (13)

Food per dog = 6.5 / 13 = 1/2

In-s [12.5K]2 years ago
3 0
1/2 for each doggo 2021
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Step-by-step explanation:

2×radius with pi, 28*pi=28 pi or 87.92

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Solve. −35x+15>720 Drag and drop a number or symbol into each box to show the solution.
vampirchik [111]

Answer:

The solution of the inequality - 35x + 15 > 720  is x

Step-by-step explanation:

Consider the given inequality

- 35x + 15 > 720

Subtract both side by 15 , we get

- 35x + 15 - 15 > 720 - 15

- 35x > 705

Multiply both sides by -1 (Reverse the inequality )

(-35x)(-1) < 705 (-1)

35x < -705

Now, divide both side by 35

\frac{35x}{35}=\frac{-705}{35}

\Rightarrow x=\frac{-141}{7}

Thus, the solution of the inequality - 35x + 15 > 720  is x

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3 years ago
Which expressions are equivalent to 4(42)? Select each correct answer. A: 4(40 + 2) B: 4(4 + 2) C: 4(4 + 20) D: 4(20 + 22)
olga2289 [7]
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The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

8 0
3 years ago
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