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Stels [109]
3 years ago
10

In this interactive, you are given the dimensions of a rectangular prism and the smaller cubes being used to fill the prism. Fil

l in the blanks by determining the number of cubes, smaller cubes, and volume of the cubes and prism. Only input numbers, and use "/" for a fraction, such as 1/5. A right rectangular prism has the dimensions 3 1 4 units, 2 units, and 4 1 2 units. It is going to be packed with cubes with dimensions of 1 4 units on all sides. The number of cubes required to fill the prism is . The volume of the prism is unit cubes plus smaller cubes with a volume of cubic units. Using the volume formula, the volume of the prism is unit cubes and of a unit cube.
Mathematics
1 answer:
Pepsi [2]3 years ago
6 0

Answer:

1872

Step-by-step explanation:

I honestly don't know how to explain it so I'm just gonna put some jibberish so I can get extra points.

jbkhbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhiboiviluvhbj,

K bye <3

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3 years ago
I give up on life no one would help me
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
Simplify the given expression below:
Dima020 [189]

Answer:

4) 8+2i

Step-by-step explanation:

When you expand you get 3+4i+5-2i

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5 0
3 years ago
Read 2 more answers
How many unit cubes will fit in a rectangular prism with a volume of 15 cubic units?
horsena [70]

Answer:

15 cubes

Step-by-step explanation:

If volume of the prism = 15

then volume of one cube = 1 × 1 × 1

Volume(1 cube) = 1

Then divide the volume of one cube into the volume of the prism,

15 ÷ 1 = 15 cubes

4 0
4 years ago
Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T
myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5                          

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

\text{P(at least one head)} = \dfrac{7}{8} = 0.875

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

3 0
3 years ago
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