The rational root theorem states that the rational roots of a polynomial can only be in the form p/q, where p divides the constant term, and q divides the leading term.
In your case, both the leading term 5 and the constant term 11 are primes, so their only divisors are 1 and themselves.
So, the only feasible solutions are
For the record, in this case, none of the feasible solutions are actually a root of the polynomial.
Answer:
Step-by-step explanatiArea of Composite Shapes. Composite shapes are shapes that have a combination of 2-D shapes. To find the area of composite shapes you just need to break down the shape into individual pieces and calculate their separate pieces then add them back together again to find a total areaon:
Using the Sine Rule:-
20 /sin 45 = BC / sin 30
BC = 20 sin 30 / sin45
= 20 * 1/2 / 1 / sqrt2
= 20 * 1/2 * sqrt2
= 10 sqrt2 answer
Answer:
18.5
Step-by-step explanation:
It says
IJ is the midsegment of the triangle. So it divides both adjacent sides in half/at modpoint.
so HF is 10 cm .. half of that is 5 cm
GH is 13 cm.. Half of that is 6.5 cm
now we have IJ = 7 cm given
add all those.. you get 18.5 cm
Answer:
D is the correct answer.......
