A) Probability that at least one of these golfers makes a hole in one on the 10th hole at the same tournament is
<span>=1−(<span>2493/2494</span><span>)^<span>5
=1-(0.99)^5
= 1- 0.96
=0.4
b) T</span></span></span><span>he probability that all of these golfers make a hole-in-one on the 10th hole at the same tournament
=</span>(<span>1/2494</span><span>)<span>5
</span></span>
which is nearly zero.
4000 is the answer to your question
The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= 
...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (
= k
k=
Read more about simultaneous equations here:
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Can you restate it or rewrite it? It doesn't have enough for me to answer this.
