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torisob [31]
3 years ago
14

15, 15, 17, 20, 21, 28 whats the mean, median and mode?

Mathematics
1 answer:
nlexa [21]3 years ago
7 0
Mean= 19 median=18.5 mode=15 sorry if it’s not right
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What is greater 7/10 or 3/6? please show work
vovikov84 [41]
What you need to do is make sure the denominators are the same so multiply 7/10 by 6. It should now be 42/60. Next multiply 3/6 by 10. It should now equal 30/60. 7/10 = 42/60. 3/6 = 30/60. 7/10 is greater. I hope this was somewhat helpful :3
3 0
3 years ago
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A rectangular cracker has a length of 5 centimeters and an area f 20 square centimeters. Find its perimeter.
iren [92.7K]

Answer:

18cm

Step-by-step explanation:

We have the length of the rectangle but we need to find the width which we'll call w. Area is a, l is length.

a = l * w

20 = 5 * w

divide both sides by 5 to cancel the multiplication by 5 on the right side

4 = w

The rectangle is going to have two sides that are the length of l, and two sides that are the the length of w. We're looking for the perimiter p.

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4 0
2 years ago
If the sum of 4040 consecutive integer numbers is 2020, find out the absolute difference between the first number and the last n
bearhunter [10]

Let x be the smallest of the consecutive integers summing to 2020. Then the largest integer in the sum is x+4039, so our answer is \boxed{4039}.

For completeness, though, let's solve for the value of x that satisfies the conditions of the problem. Recall that the sum of an arithmetic series with first term a_1, last term a_n, and n terms, is \frac{n(a_1+a_n)}{2}. Plugging in our known values gives us the equation \frac{4040(2x+4039)}{2}=2020, which simplifies to 2x+4039=1. Thus, x=-2019, so the 4040 consecutive integers are -2019,-2018,\dots,-1,0,1,\dots,2018,2019,2020. Notice how everything except the 2020 cancels out!

4 0
3 years ago
Which function has real zeros at x = –8 and x = 5?
Tcecarenko [31]

Answer:

option B is the answer . thank me later , you guys are lame

3 0
2 years ago
How do you solve 36 times <img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\sqrt{3}" ali
pantera1 [17]

Answer:

  62.3538

Step-by-step explanation:

There is nothing to solve. If you need a decimal value, you can use a calculator or table of square roots.

8 0
3 years ago
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