7h+3s=27.95 subtract 7h from both sides
3s=27.95-7h divide both sides by 3
s=(27.95-7h)/3
Then we are told:
5h+4s=23.4, using s found above makes this equation become:
5h+4(27.95-7h)/3=23.4 multiply both sides by 3
15h+4(27.95-7h=70.2 perform indicated multiplication on left side
15h+111.8-28h=70.2 combine like terms on left side
-13h+111.8=70.2 subtract 111.8 from both sides
-13h=-41.6 divide both sides by -13
h=$3.20
Answer:
473 yd^3
Step-by-step explanation:
The surface area of the square base is (11 yd)^2, or 121 yd^2.
The surface area of one of the slanting sides of the pyramid is
A = (1/2)(b)(h), which comes to A = (1/2)(11 yd)(16 yd) = 88 yd^2.
Thus, four such sides have a combined surface area of 352 yd^2.
Combining the surface areas of the slanting sides with the base area yields 473 yd^3
Because it shows how Alabamians lived in 19th to the mid 20th century, and buildings that were safe from destruction.
Answer:
Step-by-step explanation:
Simplify the equation
Since
and
we have
Answer:
A. 24.2°
Step-by-step explanation:
I'm correct if I'm rwong