x^0 + y^0
3^0 + 2^0
1 + 1 =2
your answer : 2
<u>Hint any number with the power of zero is 1</u>
Hope i helped!!! :)
Answer:
0.186
Step-by-step explanation:
6.2
<u>x 0.0</u><u>3</u>
6
1
6.2
<u>x 0.0</u><u>3</u> since 6*3=18, we have to carry the 1
86
1
6.2
<u>x 0.0</u><u>3</u>
186
6.2
<u>x 0.</u><u>0</u><u>3</u>
186
0
6.2
<u>x 0.</u><u>0</u><u>3</u>
186
00
6.2
<u>x </u><u>0</u><u>.03</u>
186
00
0
6.2
<u>x </u><u>0</u><u>.03</u>
186
+ 00 add the partial products
<u> 0</u><u>0 </u>
00186
6.2
<u>x 0.</u><u>03</u><u> </u> count how many digits are after the decimal point from each factor =3 and place in product
186
+ 00
<u> 00 </u>
00.186=0.186
<em>answer=0.186</em>
I think it would be 315. because 4.5*70..but im not sure
Answer:
4 sides
Step-by-step explanation:
A lot of math is about pattern matching. Here, you're asked if sides are the same length (one side matches another), if there are right angles (square corners), and if the number of angles or sides is 4.
You might make the observations ...
<u>pink</u>: 2 pairs of parallel sides that are the same length (4 sides). Adjacent sides are different length.
<u>orange</u>: all 4 sides are congruent and at right angles
<u>blue</u>: 2 pairs of parallel sides that are the same length (4 sides). Adjacent sides are different length.
<u>green</u>: 2 pairs of parallel sides that are the same length--4 sides and 4 right angles. Adjacent sides are different length.
__
The only feature in common is "4 sides."
Answers:
- Discrete
- Continuous
- Discrete
- Continuous
==============================================
Explanations:
- This is discrete because we can't have half a basketball, or any non-whole decimal value to represent the number of basketballs. We can only consider positive whole numbers {1,2,3,4,...}. A discrete set like this has gaps between items. In other words, the midpoint of 2 and 3 (the value 2.5) isn't a valid number of basketballs.
- This is continuous because time values are continuous. We can take any two different markers in time, and find a midpoint between them. For example, the midpoint of 5 minutes and 17 minutes is 11 minutes since (5+17)/2 = 22/2 = 11. Continuous sets like this do not have any gaps between items. We can consider this to be densely packed.
- This is the same as problem 1, so we have another discrete function. You either score a bullseye or you don't. We can't score half a bullseye. The only possible values are {1,2,3,4,...}
- This is similar to problem 2. This function is continuous. Pick any two different positive real numbers to represent the amount of gallons of water. You will always be able to find a midpoint between those values (eg: we can have half a gallon) and such a measurement makes sense.
So in short, always try to ask the question: Can I pick two different values, compute the midpoint, and have that midpoint make sense? If so, then you're dealing with a continuous variable. Otherwise, the data is discrete.
