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3 years ago

The area of a circular lake is 16 km 2

Mathematics

1 answer:

artcher [175]3 years ago

3 0

Answer:

I can't fix stupid- sorry-

Step-by-step explanation:

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What is the best approximation of the area of a circle with a diameter of 17 meters?

Nimfa-mama [501]

Area of a circle = 3.14 x r^2
=3.14 x 8.5^2
= 226.865

7 0

3 years ago

Read 2 more answers

If the figure is reflected over the line y=x, which rule is true

saveliy_v [14]

Answer:

These reflected points represent the inverse function

Step-by-step explanation:

This is just one of the rules that are true.

8 0

3 years ago

every story gets an additional 10% off the already discounted price. if an employee buys an item with an original price of $40,

ANTONII [103]

36.
Convert 10% to .1, (10 divided by 100)
then multiply 40 times .1
then subtract 4 by 40
=36

5 0

3 years ago

Bob Tina and Hadley went running. Bob ran for 3/8 hour, Tina ran for 3 4/9 hours, and Hadley ran for 4 19/29 hours. Which runnin

algol13

Answer: 3 4/9 and 4 19/29

Step-by-step explanation: Mixed fractions can be converted into improper fractions. Example: 3 1/2=

3×2+1= 7/2

So, 3 4/9= 3×9+4= 31/9

4 19/29= 4×29+19= 135/29

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3 years ago

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Recall the equation for a circle with center (h, k) and radius r. At what point in the first quadrant does the line with equatio

lina2011 [118]

Answer:

The point of intersection is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

Step-by-step explanation:

We want to find the point in QI at which the line with the equation:

$y=0.5x+5$

Intersect a circle with a radius of 3 and a center of (0, 5).

First, write the equation of a circle. The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Since our center is (0, 5), h = 0 and k = 5. The radius is 3. So, r = 3. Substitute:

$(x-0)^2+(y-5)^2=(3)^2$

Simplify:

$x^2+(y-5)^2=9$

At the point where the two equations intersect, its x-coordinate and y-coordinate will be the same. Therefore, we can substitute the equation of the line into the equation of the circle and solve for x. So:

$x^2+((0.5x+5)-5)^2=9$

Simplify:

$x^2+(0.5x)^2=9$

Square:

$x^2+0.25x^2=9$

Combine like terms:

$\displaystyle 1.25x^2=\frac{5}{4}x^2=9$

Solve for x:

$\displaystyle \begin{aligned} x^2&=\frac{36}{5} \\ x&=\pm\sqrt{\frac{36}{5}} \\ x&\Rightarrow \frac{6}{\sqrt{5}}=\frac{6\sqrt{5}}{5}\approx2.68\end{aligned}$

Note that since we are looking for the point of intersection in QI, x should be positive. So, we can ignore the negative answer.

To find the y-coordinate, substitute the x-value back into either equation. Using the linear equation:

$\displaystyle y=0.5\left(\frac{6\sqrt{5}}{5}\right)+5=\frac{3\sqrt{5}}{5}+5\approx 6.34$

So, the point of intersection in QI is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

6 0

3 years ago