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2 years ago

I'm having a hard time with this question so someone help please

Mathematics

1 answer:

bulgar [2K]2 years ago

3 0

Answer:

7.7 km

Step-by-step explanation:

This question is asking you to find the third side of a triangle in which two sides and an angle not between them are given. The law of sines provides the necessary relationships.

<h3>Law of Sines</h3>

The Law of Sines tells you that triangle side lengths are proportional to the sine of the opposite angle. For this triangle TPJ, the relation is ...

t/sin(T) = p/sin(P) = j/sin(J)

We are given T=68°, p=5.2 km, t=7.5 km, and we are asked to find the length of j, the TP distance.

<h3>Setup</h3>

We know the sum of angles in a triangle is 180°, and the sine of an angle is equal to the sine of its supplement. This lets us fill in the Law of Sines equation like this:

7.5/sin(68°) = 5.2/sin(P) = j/sin(68°+P) . . . . . solve for j

<h3>Solution</h3>

This can be solved in two steps. First, we find angle P, then we use that to find length j.

sin(P) = 5.2/7.5 × sin(68°) ≈ 0.642847

P = arcsin(0.642847) ≈ 40.0045°

Now, we can find j:

j = 7.5 × sin(68° +40.0045°)/sin(68°) ≈ 7.693 . . . km

The distance from the tower to the plane is about 7.7 km.

<em>Additional comment</em>

We have used T, P, and J to refer to the vertices at the tower, plane, and jet.

The triangle can also be solved using the Law of Cosines. In that case, the missing side will be the solution to a quadratic equation with irrational coefficients.

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Answer:

$t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73$

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If we compare the p value and a significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=86.7$ represent the average life for the sample

$s=8.6$ represent the population standard deviation

$n=45$ sample size

$\mu_o =83.2$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a two tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \leq 83.2$

Alternative hypothesis : $\mu > 83.2$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73$

Give the appropriate conclusion for the test

First we need to calculate the degrees of freedom given by:

$df=n-1=45-1=44$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{44}>2.73)=0.0045$

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