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Alecsey [184]
3 years ago
14

The nth shell holds a minimum number of 2n2 electrons True False Other:

Chemistry
1 answer:
BARSIC [14]3 years ago
8 0

Answer: The statement the  n^{th} shell holds a minimum number of 2n^{2} electrons is true.

Explanation:

The alphabet 'n' denotes the principal quantum number whose value can be equal to 1, 2, 3, and so on but can never be zero.

Basically, 'n' is the number of shell of an atom and total number of orbitals present in a shell is n^{2}.

Each orbital can hold up to a maximum of wo electrons. Hence, the n^{th} shell can hold a minimum number of 2n^{2} electrons.

Thus, we ca conclude that the statement the  n^{th} shell holds a minimum number of 2n^{2} electrons is true.

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What is refraction? * Bending of light<br> Reflection of light
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6 0
3 years ago
Read 2 more answers
What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?
Marina86 [1]

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

6 0
3 years ago
Drawing Conclusions
Dmitrij [34]

<u>Answer:</u>

<em>The situation given here is imaginary such that the life of Rock has to be found using the half-life of the element lokium that has been found inside the rock. </em>

<u>Explanation:</u>

Half-life of any material is the amount of time taken by that particular material to decay. Now the amount of lokium found in rock can show after how many half-lives this amount has been left out.

The time elapsed will be log (L) atoms X half-life.

4 0
3 years ago
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