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nevsk [136]
3 years ago
13

When equal moles of an acid and a base are mixed, after reaction the two are compounds are said to be at the _______________.

Chemistry
2 answers:
Ber [7]3 years ago
4 0

Answer: equivalence point

otez555 [7]3 years ago
3 0

Answer: equivalence point

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Is putting food coloring in water a chemical change?
nata0808 [166]
Yes, Yes it is. Food coloring has chemicals in it
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Theresa creates an experiment where she mixes two red-colored substances together in a container and observes the solution slowl
Goshia [24]

Answer: Answer (A)    

Explanation:

3 0
3 years ago
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100gm of a 55% (M/M) nitric acid solution is to be diluted to 20% (M/M) nitric acid.
yawa3891 [41]

Volume of H₂O added = 175 ml

<h3>Further explanation</h3>

Given

100 gm of a 55% (M/M)  and 20% (M/M) nitric acid solution

Required

waters added

Solution

starting solution

mass H₂O = 45%=45 g

%mass of H₂O in new solution = 100%-20%=80%

Can be formulated for %mass H₂O :

\tt \dfrac{45+x}{100+x}=80\%\\\\45+x=0.8(100+x)\\\\45+x=80+0.8x\\\\35=0.2x\rightarrow x=175~g

For water mass=volume(density = 1 g/ml)

So volume added = 175 ml

7 0
3 years ago
Please Help I need an explanation on how to do this
nydimaria [60]

Balanced equation(That should be NaClO_3)

\\ \rm\Rrightarrow Cl_2+2NaOH\longrightarrow NaCl+NaClO_3+H_2O

Remember that it's a ionic equation not general equation

So

We have to balance it accordingly

5 0
2 years ago
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How many grams of water can be formed from the reaction of 8.76 grams of H2 with 10.5 liters of O2 (at STP) according to the bal
Kisachek [45]

Answer:

16.9g of H₂O can be formed

Explanation:

Based on the chemical reaction, 2 moles of H₂ react per mole of O₂. To anser this question we must find limiting reactant converting the mass and volume of each reactant to moles:

<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>

8.76g * (1mol / 2.016g) = 4.345 moles

<em>Moles O₂:</em>

PV = nRT

PV/RT = n

P = 1atm at STP

V = 10.5L

R = 0.082atmL/molK

T = 273.15K at STP

n = 1atm*10.5L / 0.082atmL/molK*273.15K

n = 0.469 moles of oxygen

For a complete reaction of 4.345 moles moles of hydrogen are required:

4.345 moles H2 * (1mol O2 / 2mol H2) = 2.173 moles of O2 are required. As there are just 0.469 moles, Oxygen is limiting reactant

Now, 1 mole of O2 produce 2 moles of H2O. 0.469 moles will produce:

0.469 moles O₂ * (2 moles H₂O / 1mol O₂) = 0.938 moles H₂O.

The mass is -Molar mas H₂O = 18.01g/mol-:

0.938 moles * (18.01g/mol) =

<h3>16.9g of H₂O can be formed</h3>
8 0
3 years ago
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