?? Is that the whole question?
Answer:
1. C4H8 + 6O2 -----> 4CO2 + 4H20
2. 3836.77 kcal
Explanation:
1. Balanced equation for the complete combustion of cyclobutane:
C4H8 + 6O2 -----> 4CO2 + 4H20
2. Heat of combustion of cyclobutane = 650.3 kcal/mol
Molecular weight of cyclobutane, C4H8 = 56.1 g/mol
Mole of C4H8 : mass of cyclobutane/Molecular weight of cyclobutane
Mole of C4H8 = 331/56.1 = 5.9 mol
Energy released during combustion = 5.9 mol × 650.3 kcal/mol = 3836.77kcal
Therefore the energythat is released during the complete combustion of 331 grams of cyclobutane is 3836.77kcal
Answer: , 4 molecules of ammonia, NH3(g) is produced; 2 molecules of ammonia, NH3(g) is produced respectively
Explanation:
The balanced equation is stated below N2(g) + 3H2(g) → 2NH3(g)
1 mole of N2(g) reacts with 3 moles of H2(g) to yield 2 moles of NH3(g)
1) If 2 molecules of N2 react, then the balanced equation will be
2N2(g) + 6H2(g) → 4NH3(g)
Thus, 4 molecules of ammonia, NH3(g) is produced
2) If 3 molecules of H2 react, then the balanced equation will be
N2(g) + 3H2(g) → 2NH3(g)
Thus, 2 molecules of ammonia, NH3(g) is produced
Energy and the nature of the current
