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katrin [286]
2 years ago
8

Brainliest!!

Mathematics
1 answer:
AlladinOne [14]2 years ago
6 0

Answer:

d

Step-by-step explanation:

BC supplementary means they add up to 180 and answer d adds up to 180

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Quick easy one to do!! 15pts​
Lyrx [107]

Answer:

34

Step-by-step explanation:

90-56=34

3 0
2 years ago
Read 2 more answers
What is 0.95 in simplest form
solong [7]
0.95 \times \frac{100}{100} = \frac{95}{100} = \frac{19 \times 5}{20\times 5}\\\\ = \boxed{\bf{\frac{19}{20}}}

0.95 in simplest form is 19/20
5 0
3 years ago
Help me do question 9 and 10 I am 6th grade. Please
Phoenix [80]

Answer:

Step-by-step explanation:

9 - ratio 3:5

10 1/8 + 1/4 = 1/8 + 2/8 = 3/8 of the pizza eaten

so 5/8th of the pizza is left

8 0
3 years ago
If A and B are matrices and AB = I, which of the following represents the value of B?
Ratling [72]
If the product of 2 matrices are I this means that B is inverse matrix of A.
the matrix A has been given 
if we put symbols for the numbers in matrix A as shown below;
\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] 

we need to first find the determinant (D)
D = ad - bc
where a = -1 , b = 4, c = -3 and d = 8
substituting these values 
D = -1x8 - (4x-3)
   = -8 +  12 = 4 
to find the inverse we need to exchange a and d and then multiply both b and c by -1
\left[\begin{array}{ccc}8&-4\\3&-1\\\end{array}\right]
and then have to divide all the terms in matrix by determinant (4)
\left[\begin{array}{ccc} \frac{8}{4} & \frac{-4}{4} \\  \frac{3}{4} & \frac{-1}{4} \\\end{array}\right]
the simplified inverse matrix B is;
\left[\begin{array}{ccc} 2 & -1 \\ \frac{3}{4} & \frac{-1}{4} \\\end{array}\right]

6 0
3 years ago
Read 2 more answers
URGENT!! WILL GIVE BRAINLIEST
Paha777 [63]

Answer:

She made an error when using the zero pair.

Step-by-step explanation:

In step 2, Carianne added 4 to the right side and subtracted 4 on the left side, which is completely changing the equation. By definition, your zero pair must have a difference of zero. She need to add 4 to both sides to continue; when manipulating algebra you need to do the same thing to both sides of an equation, otherwise you're just changing the equation.

8 0
3 years ago
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