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jok3333 [9.3K]
3 years ago
5

If A and B are matrices and AB = I, which of the following represents the value of B?

Mathematics
2 answers:
Ratling [72]3 years ago
6 0
If the product of 2 matrices are I this means that B is inverse matrix of A.
the matrix A has been given 
if we put symbols for the numbers in matrix A as shown below;
\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] 

we need to first find the determinant (D)
D = ad - bc
where a = -1 , b = 4, c = -3 and d = 8
substituting these values 
D = -1x8 - (4x-3)
   = -8 +  12 = 4 
to find the inverse we need to exchange a and d and then multiply both b and c by -1
\left[\begin{array}{ccc}8&-4\\3&-1\\\end{array}\right]
and then have to divide all the terms in matrix by determinant (4)
\left[\begin{array}{ccc} \frac{8}{4} & \frac{-4}{4} \\  \frac{3}{4} & \frac{-1}{4} \\\end{array}\right]
the simplified inverse matrix B is;
\left[\begin{array}{ccc} 2 & -1 \\ \frac{3}{4} & \frac{-1}{4} \\\end{array}\right]

Stels [109]3 years ago
5 0

Answer:

4th option D

Step-by-step explanation:

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Factor completely 3x^2+9x-3<br>3(x^2+3)<br>3(x^2+3-1)<br>3x(x^2+3x-1)<br>prime​
Firdavs [7]

Answer:

Answer from the answer data to choose from

<h2>3(x² + 3x - 1)</h2>

Factor completely

3\left(x+\dfrac{3-\sqrt{13}}{2}\right)\left(x+\dfrac{3+\sqrt{13}}{2}\right)

Step-by-step explanation:

3x^2+9x-3=(3)(x^2)+(3)(3x)-(3)(1)\\\\=(3)(x^2+3x-1)\\\\\text{For}\ x^2+3x-1\ \text{use the quadratic formula}\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x^2+3x-1\to a=1,\ b=3,\ c=-1\\\\x=\dfrac{-3\pm\sqrt{3^2-4(1)(-1)}}{2(1)}=\dfrac{-3\pm\sqrt{9+4}}{2}=\dfrac{-3\pm\sqrt{13}}{2}=-\dfrac{3\pm\sqrt{13}}{2}\\\\3x^2+9x-3=3\left(x+\dfrac{3-\sqrt{13}}{2}\right)\left(x+\dfrac{3+\sqrt{13}}{2}\right)

4 0
3 years ago
Please help me with this.
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Answer:

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Step-by-step explanation:

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