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Pavel [41]
2 years ago
14

How to solvee ????? PPLLEASEEEEE

Mathematics
2 answers:
Kipish [7]2 years ago
5 0
If they are all in a line then we can find the equation of their line using: y = mx + b

First find m using points (2,5) and (3,3)

m = (5-3)/(2-3) = 2/-1 = -2

Now using (3,3) and m= -2 to solve for b:

3 = -2(3) + b
3 = -6 + b
9 = b

So our equation is y = -2x + 9
That is the solution for question b)

Now to find the mystery point, solve:

1 = -2x + 9
-8 = -2x
4 = x

So our mystery point is (4,1)

So for part a) the answer is k = 4
Crank2 years ago
3 0
K=4. That is the answer
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Ann and Pat have 3 cupcakes to share. They cut each cupcake into 2 equal parts.
Rama09 [41]

Answer:

6

Step-by-step explanation:

3+3 maybe :) .

3 0
3 years ago
Read 2 more answers
Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp
Maslowich

If p(3-2i)=0, then complex number 3-2i is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated 3+2i is also a root of polynomial.

Then the polynomial will be of a form

p(x)=(x-(3-2i))(x-(3+2i))(x-a).

Since p(0)=-52, then

-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.

Therefore,

p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.

3 0
2 years ago
What will the finance charge be on Hannah's computer purchase? (Do not include<br> sales tax)
k0ka [10]

Answer:

She would be paying $2,622 total.

Step-by-step explanation:

1. To get how much she'd be paying for 24 months, all you have to do is multiply 24 times 95.

2. To get the down payment you had to ask yourself what's 15% of 2,280. 15% of 2280 is 342.

3. Add those together and you'd get the total payment.

Simple.

Oh and gimme Brainliest if it's correct.

8 0
2 years ago
How do i solve this in the quadratic formula?
liraira [26]
Firstly mines 2x for 2 side
And combine 1 for 2 side
Result 6x^2+17x+5
So
(3x+1)(2x+5)=0
X=-1/3 or x=-5/2
6 0
3 years ago
Consider the differential equation
Gennadij [26K]

The first solution is quadratic, so its derivative y' on the left side is linear. But the right side would be a polynomial of degree greater than 1, so this is not the correct choice.

The third solution has a similar issue. The derivative of √(x² + 1) will be another expression involving √(x² + 1) on the left side, yet on the right we have y² = x² + 1, so that the entire right side is a polynomial. But polynomials are free of rational powers, so this solution can't work.

This leaves us with the second choice. Recall that

1 + tan²(x) = sec²(x)

and the derivative of tangent,

(tan(x))' = sec²(x)

Also notice that the ODE contains 1 + y². Now, if y = tan(x³/3 + 2), then

y' = sec²(x³/3 + 2) • x²

and substituting y and y' into the ODE gives

sec²(x³/3 + 2) • x² = x² (1 + tan²(x³/3 + 2))

x² sec²(x³/3 + 2) = x² sec²(x³/3 + 2)

which is an identity.

So the solution is y = tan(x³/3 + 2).

4 0
2 years ago
Read 2 more answers
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