I'm taking the liberty of editing your function <span>v = e5xey: It should be
</span>
<span>v = e^5x^ey, with " ^ " indicating exponentiation.
</span>
Did you mean e^(5x) or (e^5)x? I'll assume it's e^(5x).
The partial of v = e^(5x)e^y with respect to x is e^(5x)(5)*e^y, or 25x*e^y.
The partial of v = e^(5x)e^y with respect to y is e^(5x)e^y.
0.0006 would be your answer based on the order you put them in.
Answer:
m=3/4
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let y be the total charge and x no of hours spent for cutting the lawn,
Then for Allan we have the equation as
y = 8.50x+15
SInce 15 is the fixed charge and 8.50 is charged per hour we get the above equation for Allan.
Next similarly for Taylor, we have fixed charges 12 and variale 9.25
y =9.25x+12
When Taylor total charges is greater than Allan's total charge
we have 9.25x+12>8.5x+15
Simplify to get
0.75x>3
Or x>4
Whenever x i.e. no of hours exceed 4, Taylor charges will be greater than that of Allan
Answer:
Step-by-step explanation:
<u>Given equation:</u>
<u>Simplify, then solve:</u>
- -11 2/3 * (-4 1/5)
- = -35/3 * (-21/5)
- =
- = 735/15
- = 49.
Your answer is A. 49.
