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Pavel [41]
3 years ago
9

If I buy a dozen cupcakes for $16.80, How much will 16 cupcakes cost.​

Mathematics
1 answer:
skad [1K]3 years ago
7 0

Answer:

i aint gon lie evolution and natural selection?

Step-by-step explanation:

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An opaque bag contains 5 green marbles 3 blue marbles and 2 red marbles. What is the probability of randomly picking out a marbl
anastassius [24]

Answer= .2 probability

Explanation: Since there is a total of 10 marbles, and 2 are red, you would divide the red marbles (2) out of the total marbles (10) which would get u .2. Since it’s asking for probability, we would keep .2 a decimal.

6 0
3 years ago
Jess is comparing fractions, which fraction is greater than 5/6?<br> A) 7/8B) 4/5C) 3/4D) 2/3
levacccp [35]
I think the answer is D

                                                                    
6 0
3 years ago
Read 2 more answers
How many solutions does the system have? \begin{cases} 3x+y=8 \\\\ 2x+2y=8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ 3x+y=8 2x+2y=8 ​ Choose 1
ELEN [110]

Answer:

This system has one solution (x=2 and y=2), then the answer is A.

Step-by-step explanation:

The system of equations is:

3x+y=8 (1)

2x+2y=8 (2)

Let's multiply the first equation by 2 and subtract it to the second equation  

6x-2x+2y-2y=16-8

4x=8  

x=2

Using this value in (1) we can find y.

3(2)+y=8

6+y=8

y=2

Therefore, this system has one solution (x=2 and y=2), the answer is A.

I hope it helps you!

3 0
3 years ago
Marie will earn $15 per hour at a new job.
denis-greek [22]
What’s the question?
7 0
3 years ago
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If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
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