Answer:
New bed dimension of bed 0.5 ft, 0.25 ft
New bed dimension of room 1.16 ft, 1.33 ft
Step-by-step explanation:
Given data:
bed dimension is given as 6 ft by 3 ft
room dimension is given as 14 ft 16 ft
according to the given information , new dimension of the room and bed will be 1/12 times of actual dimension. therefore we have
New bed dimension of bed 
= 0.5 ft, 0.25 ft
New bed dimension of room 
= 1.16 ft, 1.33 ft
Answer:
3.438
Step-by-step explanation:
5.73 × 0.6 = 3.438
The domain of the function is \[A \ge0\] If A is negative we get an imaginary number for the radius. This makes sense because the area of a circle cannot be negative.
Answer:
Step-by-step explanation:
1). Step 4:
![x=\sqrt[3]{5^4}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5E4%7D)
[Since, ![a^{\frac{1}{3}}=\sqrt[3]{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7Ba%7D)
]
![x=\sqrt[3]{5\times 5\times 5\times 5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5Ctimes%205%5Ctimes%205%5Ctimes%205%7D)
Step 5:
![x=\sqrt[3]{(5)^3\times 5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%285%29%5E3%5Ctimes%205%7D)
![x=\sqrt[3]{5^3}\times \sqrt[3]{5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5E3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B5%7D)
2). He simplified the expression by removing exponents from the given expression.
3). Let the radical equation is,
Step 1:
Step 2:
Step 3:
Step 4:
4). By substituting in the original equation.
There is no extraneous solution.
