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3 years ago

Three times a number h is at least -12 .

Mathematics

1 answer:

pashok25 [27]3 years ago

3 0

Answer:

Im certain The answer is -4

Let me know if im wrong :)

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WILL MARK BRAINLIST

Elan Coil [88]

1. The first 10 multiples of 13 are 13, 26, 39, 52, 65, 78, 91, 104, 117, and 130.
2. x - 5
3. x + 80

5 0

3 years ago

If f(x)=3x-1 and g(x)=x+2, find (f-g)(x)

siniylev [52]

Answer:

(f - g)(x) = 2x - 3

Step-by-step explanation:

(f - g)(x)

= f(x) - g(x)

= 3x - 1 - (x + 2)

= 3x - 1 - x - 2

= 2x - 3

7 0

1 year ago

The spinner of the compass is two congruent isosceles triangles connected by their bases as shown in the diagram. The base of ea

a_sh-v [17]

Answer:

fff

Step-by-step explanation:

By pythagorean theorum we calculate the height:

$\sqrt{5^2-1^2}$

= $\sqrt{24}$ = height of triangle

area of triangle = base * height

area = $2*\sqrt{24}$

There are two triangles so:

$2*2*\sqrt{24}=4\sqrt{24}$

Multiply this by 13.25 to get total cost:

=$259.65

6 0

3 years ago

Read 2 more answers

How do i solve this step by step? 3( q – 3 ) = 6

mote1985 [20]

Answer:

3q-9=6

3q=9+6

3q=15

q=5

7 0

3 years ago

A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v

BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: Confidence Interval is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

$p_{1}=\frac{30}{120}=0.25$

$p_{2}=\frac{32}{160}=0.2$

Second, calculate standard deviation for each proportion:

$\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395$

$\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316$

Now, we calculate standard error for difference:

$SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}$

$SE=\sqrt{0.0395^{2}+0.0316^{2}}$

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

$p_{1}-p_{2}$ ± z-score.SE

$0.25-0.2$ ± $1.645(0.0505)$

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = $-0.0332$

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is $[-0.0332,0.1332]$ .

8 0

3 years ago