Answer:
= 105(x+2)/33-x
Step-by-step explanation:
Given the expression
[3(x+2)*10*7]÷70 - 2(x+2)
= 3(x+2)*70÷70 - 2(x+2)
= 210(x+2)/70-2x-4
= 210(x+2)/66-2x
= 210(x+2)/2(33-x)
= 105(x+2)/33-x
Answer:
Step-by-step explanation:
Answer:
y=3x- 3/2
Step-by-step explanation:
4.2x−1.4y=2.1
Subtract 4.2x from each side
4.2x-4.2x−1.4y=-4.2x+2.1
-1.4y = -4.2x +2.1
divide each side by -1.4
-1.4y/-1.4y = -4.2x/ -1.4 +2.1/-1.4y
y=3x- 3/2
Answer:
x=12 or x= -12 (answer A)
Step-by-step explanation:
|x| – 5 = 7
|x| = 12
x=12 or x= -12 (answer A)
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
