There are 135 people and three door prizes. how many ways can door prizes of $7,500, $750 and $75 be distributed?
1 answer:
Answer: 2405970 ways
Step-by-step explanation:
When the order of selecting r individuals out of n individual , we use permutations.
The number of permutations of r things taking out of n things is given by :-
Given : There are 135 people and three door prizes .
i.e. n= 135 , r= 3
Then, the total number of ways =
Hence, there are 2405970 ways to distribute door prizes of $7,500, $750 and $75 .
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Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to