Which is nearest to the perimeter of WXYZ

Which expression has the greatest value when x=3

Luden [163]

Answer:

The third expression: (2x)^3

Step-by-step explanation:

Plug in 3 for x in each expression

2x^3

2(3)^3

Use PEMDAS

2 (3 × 3 × 3)

2 (9 × 3)

2 (27)

54

2x^3 + 5

(The last expression told us 2x^3 = 54 so feel free to use this information to make life easier)

54 + 5

59

(2x)^3

(2 × 3)^3

Use PEMDAS

6^3

6 × 6 × 6

36 × 6

216

(x - 1)^3

(3 - 1)^3

Use PEMDAS

2^3

2 × 2 × 2

4 × 2

8

216 is the greatest value so the third expression is the answer

7 0

2 years ago

Mr.Sampson fills the family pool with water for the summer, after two hours, the water has reached the depth of 2.5 feet.After t

scoray [572]

This question is incomplete

Complete Question

Mr Sampson fills the family pool with water for the summer.After two hours,the water has reached a depth of 2.5 feet. After three hours,the water level has risen to 3 3/4 feet.If the relationship between time and water depth is proportional,what is the constant of proportionality?

Answer:

1.33

Step-by-step explanation:

Time is proportional to Depth

Hence:

T ∝ D

T = kD

Where k is the constant of proportionality

After two hours,the water has reached a depth of 2.5 feet. After three hours,the water level has risen to 3 3/4 feet.

Total number of hours now is 3 + 2 = 5 hours

5 = k × 3 3/4

5 = k × 3.75

k = 5/3.75

k = 1.33

8 0

3 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm