The function you seek to minimize is
()=3‾√4(3)2+(13−4)2
f
(
x
)
=
3
4
(
x
3
)
2
+
(
13
−
x
4
)
2
Then
′()=3‾√18−13−8=(3‾√18+18)−138
f
′
(
x
)
=
3
x
18
−
13
−
x
8
=
(
3
18
+
1
8
)
x
−
13
8
Note that ″()>0
f
″
(
x
)
>
0
so that the critical point at ′()=0
f
′
(
x
)
=
0
will be a minimum. The critical point is at
=1179+43‾√≈7.345m
x
=
117
9
+
4
3
≈
7.345
m
So that the amount used for the square will be 13−
13
−
x
, or
13−=524+33‾√≈5.655m
Answer:
Step-by-step explanation:
<u>Given system:</u>
In order to solve it graphically, graph both lines and find the point of their intersection.
Graphing easy if you plot the x- and y- intercepts and connect them with a line.
<em>See attached.</em>
Both lines have same x-intercept, which is also the solution: (2, 0)
Well, we can make it 3 + 5
3 + 5 = 8
Hope I helped!
~ Zoe
Answer:
already answered
Step-by-step explanation: