Answer:
60 m
Explanation:
After 3 seconds of travel at 20 m/s, the projectile is 3·20 = 60 meters horizontally from the cannon.
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The vertical height after 3 seconds is 0.9 m, so the straight-line distance from cannon to target is √(60^2 +0.9^2) ≈ 60.007 meters.
Answer:
1 million hahahahahahahahhahah
Given:
ΔT = 38 - 26 = 12°C, temperature change
Q = 11.3 J, heat input
c = 0.128 J/(g-°C), specific heat of lead
Let m = the mass of the lead.
Then
Q = m*c*ΔT
(m g)*(0.128 J/(g-°C))*(12 °C) = 11.3 J
1.536m = 11.3
m = 7.357 g
Answer: 7.36 g (2 sig. figs)
The answer is counter clockwise relative to the polaris. The polaris, also known as northern star would seem a bit more stable on the night sky as the point of vision is up north, the stars however around this would look as if it was rotating, left to right but since the earth is round in shape it follows a circular pattern.