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Butoxors [25]
2 years ago
8

Differentiate between moments and momentum​

Physics
1 answer:
marshall27 [118]2 years ago
5 0

Answer: Momentum applies to objects in motion and is the product of mass and velocity. It is not the energy, but the variables are the same. By contrast, "moment" is an expression of the "rotational force" caused by a force acting at some distance from a fulcrum.

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Do you get this ?????
Jet001 [13]

The first one is actually 10 times as big as the second one.

Because of their places, the first one means 6000, and the second one means 600.

8 0
3 years ago
If we were to illuminate them only with light from the Balmer transition considered above, would the solar panels produce a curr
Ugo [173]

Answer:

No

Explanation:

The reason why no current is produced are basically that, the wavelengths of light in the Balmer transition are reflected, not absorbed in solar panels, hence no current is produced.

The Balmer series consists of lines in the visible spectrum. It corresponds to emission of a photon of light when electrons descend from higher energy levels to the n=2 level in the hydrogen spectrum. The various wavelengths in the Balmer series can be separated by a prism since they are all in the visible region of the electromagnetic spectrum.

In solar panels, light corresponding to the wavelengths in the Balmer series is merely reflected by the panel and not absorbed. Since light is not absorbed, no current can be produced when the panel is irradiated with light corresponding to the wavelengths in the Balmer series.

6 0
3 years ago
If you have to apply 40 N of force to a crowbar to lift a rock that weighs 400 N, what is the actual mechanical advantage of the
Sauron [17]
The AMA is calculated as:
AMA = force obtained / force applied
AMA = 400 / 40
AMA = 10
6 0
3 years ago
Read 2 more answers
Look at the circuit diagram. Which of these components is part of the circuit?
Roman55 [17]

Answer:

b ac power source

Explanation:

ieififuffucjcjcicogore8e8e9e9e9e9ew0ww0w0w

7 0
3 years ago
A uniform rod of length L is pivoted at L/4 from one end. It is pulled to one side through a very small angle and allowed to osc
ludmilkaskok [199]

Answer:

T= 4.24sec

Explanation:

We are going to use the formula below to calculate.

T=2\pi \sqrt{\frac{L}{g} }

Where T is period

           L is length of rod

       g is acceleration due to gravity =     9.8m/s^{2}

From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this L_{O}

L_{O} = 3/4 * 5.95m

        = 4.4625m

thus   T=2\pi \sqrt{\frac{L_{O} }{g} }

          T=2\pi \sqrt{\frac{4.4625 }{9.8} }

          T= 4.24sec

8 0
3 years ago
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