9514 1404 393
Answer:
x = 10·cos(θ) -4·cot(θ)
Step-by-step explanation:
Apparently, we are to assume that the horizontal lines are parallel to each other.
The relevant trig relations are ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
If the junction point in the middle of AB is labeled X, then we have ...
sin(θ) = 4/BX ⇒ BX = 4/sin(θ)
cos(θ) = x/XA ⇒ XA = x/cos(θ)
Then ...
BX +XA = AB = 10
Substituting for BX and XA using the above relations, we get
4/sin(θ) +x/cos(θ) = 10
Solving for x gives ...
x = (10 -4/sin(θ))·cos(θ)
x = 10·cos(θ) -4·cot(θ) . . . . . simplify
_____
We used the identity ...
cot(θ) = cos(θ)/sin(θ)
<span>4.953 is bigger compared to 4.951 because 3 is bigger than 1.
Hope this helps!</span>
Answer:
(-1,1)
Step-by-step explanation:
x + 9y = 8
-6x - 9y = -3
Add the two equations together to eliminate y
x + 9y = 8
-6x - 9y = -3
---------------------
-5x = 5
Divide by -5
-5x/-5 = 5/-5
x = -1
Now solve for y by substituting into the first equation
x+9y = 8
-1 + 9y =8
Add 1 to each side
-1+1 + 9y = 8+1
9y=9
Divide each side by 9
9y/9 = 9/9
y = 1
