Answer:
s = 71 mph, and s+9 = f = 80 mph
Step-by-step explanation:
The distances the two busses travel add up to 604 mi.
Letting f be the faster speed and s the slower. Then f = s + 9 (mph).
Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi. Solve this for s:
4s + 36 + 4s = 604 mi, or 8s = 568. Finally, s = 71 mph, and s+9 = f = 80 mph.
Answer:
The takt time is 576 seconds per cooler
Step-by-step explanation:
Knowing the formula
Takt Time = (Available production time in seconds) / (Required output time in seconds)
Available production time in seconds = 8*60*60
Required output time in seconds = 5050
Takt Time = (8*60*60) / (50) = 576 seconds per cooler
Answer:
2(x-15)
Step-by-step explanation: