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earnstyle [38]
3 years ago
12

HELP ME PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer:

19y+5

Step-by-step explanation:

Combine like terms look for all the numbers that have y attached and combine them

7y +12y=19y

Look for terms where nothing is attached it's just the number combine them

6-1=5

Put all together again and you get:

19y+5

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A probable passes through (3,0) (-2,3) and (-1,4) what function does this represent
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Thought you'd want to know:  If you're talking about parabolas, it's parabolas, not probables.  ;)

The standard equation of a a quadratic is  y = ax^2 + bx + c.  We need to find the values of the coefficients a, b and c.

Taking the first point:  When x=3, y=0, so write 0 = a(3)^2 + b(3) + c, or
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Do the same for points (-2,3) and (-1,4).

You will have obtained three linear equations in a, b and c:

3= a(-2)^2 + b(-2) + c, or 3 = 4a - 2b + 1c, also

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I used matrix operations to solve this system.  The results are:

a= -2/5, b= 1/5, c= 21/5

and so the function f(x) is f(x) = (-2/5)x^2 + (1/5)x + 21/5.
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Step-by-step explanation:

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