(x^1/8 y^1/4 z^1/2)^8
(8 √x 4 √y √z^8)
(8 √x 8 √y^2 8 √z^4)^8
8 √xy^2z^4^8
Solution: xy^2 z^4
Answer:
Step-by-step explanation:
Given data of x and y are tabulated and slope and intercept found out
X Y
26 540
27 555
33 575
29 577
29 606
34 661
30 738
40 804
22 496
SLOPE 15.89351852
Intercept 140.0833333
a) Regression equation is
y =15.89x+140.08
b) Enclosed
c) POsitive linear relation
d) When x increses by 1 unit y increases by 15.89 units
e) predictor is x and response is y
f) No outliers.Potential are
26 540
27 555
33 575
29 577
g) whenever we have x value we substitute in regression equation and find y
g)
Answer:
they will hurt your fellings
Step-by-step explanation:
8/15 = 56/105
This may be solved using proportion.
a/b = c/d
ad = bc where cross products are equal.
a = 8
b = f
c = 56
d = 105
ad = bc
8*105 = f*56
840 = 56f
840/56 = 56f/56
f = 15
56 ÷ 7 = 8
105 ÷ 7 = 15
9514 1404 393
Answer:
a) average rate = (total distance)/(total time)
b) Rave = 2·R1·R2/(R1 +R2)
c) cheetah's average rate ≈ 50.91 mph
Step-by-step explanation:
a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...
First leg distance: AB = 70·t1 ⇒ t1 = AB/70
Second leg distance: AB = 40·t2 ⇒ t2 = AB/40
The average rate is the ratio of total distance to total time:
average rate = (AB +AB)/(t1 +t2)
average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)
average rate = 560/11 = 50 10/11 . . . mph
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No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.
b) For two rates over the same distance (as above), the average is their harmonic mean:
average rate = 2r1·r2/(r1+r2)
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c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.
