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3 years ago

What is the equation of this line

Mathematics

1 answer:

eduard3 years ago

4 0

What line? try uploading an equation

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Which of the following sets of points would create a rectangle when connected?

OleMash [197]

CORRECT ANSWER: D
Explanation: I just did the work, but the y’s on the first two match up and they match in the second two. It’s D

4 0

3 years ago

8 - 4y + (-2y) + 5 What is this answer please tell me

Irina-Kira [14]

Answer:

13 - 6y

Step-by-step explanation:

8 - 4y + (-2y) + 5 = 13 - 6y

8 0

3 years ago

Read 2 more answers

How much is3 dimes and a quarter

hram777 [196]

Answer:

55 cents

Step-by-step explanation:

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3 years ago

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A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a

Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

$p^4 (1-p)$

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

$(1-p)^4p$

Therefore the probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

7 0

3 years ago

If 0 = 6n -36 what is the value of n -5

juin [17]

0=6n- 36

6n-36

6 x-5-36

35-36

n=-1
I hope this help

8 0

3 years ago