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2 years ago

8

Cuantos parque solares hay en china

1 answer:

emmainna [20.7K]2 years ago

7 0

The translation of the question is:

<h3>What are solar parks?</h3>

The solar park is a concentrated zone of development of solar power generation projects and provides developers an area that is well characterized, with proper infrastructure and access to amenities and where the risk of the projects can be minimized.

How many solar parks are there in China?

Huanghe Hydropower Hainan Solar Park – 2.2GW
Tengger Desert Solar Park – 1.55GW
Datong Solar Power Top Runner Base – 1.1GW
Yanchi Ningxia Solar Park – 1GW
Longyangxia Dam Solar Park – 850MW

Learn more about solar energy here:

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IF a 50 pound bag costs $6.36, which expression shows how much 1 pound costs?

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6.36 Divided by 50 eqauls 0.1272

Step-by-step explanation:

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3 years ago

Henry makes $7.00 per hour before taxes working at a movie theater. On Tuesday, Henry worked 5 hours, and then he worked 4 hours

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Step-by-step explanation:

1hr = $7.00

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3 years ago

R(-5, 5) S(1, 7) T(2, 4) U(-4, 2)

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3 years ago

Please solve both of these questions

Alex

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3 years ago

a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

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6 0

2 years ago

Read 2 more answers