8 is 1/6 of 8/6 = 1 1/3
125 is 5/10 of 625/10 = 62 1/2
32 is 4/10 of 128/10 = 12 4/5
Answer:
See explanation
Step-by-step explanation:
You are given the equation 
1. Add 8 negative x-tiles to both sides of the equation to create a zero pair on the left side. The equation then will have form
2. Add 5 negative unit tiles to both sides of the equation to create a zero pair on the right side. The equation now is
3. Divide both sides by 3:
Step-by-step explanation:
first u find the angles and then u use some low divide the length of triangle by sin of opposite angles
12.568% is the correct answer
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
