Find the area of a isosc olese triangle the numbers are 13 and 10
1 answer:
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T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)
A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.
Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)
and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)
So, the matrix of the transformation is
The inverse of the matrix is
So, the Inverse Transformation is given by
So, no option is correct. And the answer is
Learn more about linear transformations here-
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From my own solution, my answer is closest to D<span>. 1951 yd; 27°
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>
Pls. see my attachment.
In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite
From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.
I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.
Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.
With regards to the angle of depression, I used this formula:
tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>
</span>
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>
Pls. see my attachment.
In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite
From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.
I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.
Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.
With regards to the angle of depression, I used this formula:
tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>
</span>