5) So for parallelogram ABCD, ∠B ≅ ∠D, and ∠A ≅ ∠C. Further, ∠B and ∠A are supplementary (i.e., their sum is 180°), and ∠D and ∠C are also supplementary.
So, we have that m∠B = m∠D. Therefore,

Now, let's substitute for x back into the expression for either ∠B or ∠D to find it's angle measure.
m∠B =

Now, remember that ∠B or ∠D are supplements of ∠A.
So, m∠B + m∠A = 180°.
That means m∠A = 180° – 72° = 108°.
That seems reasonable, because A appears to be an obtuse angle.
Answer:
<h2>Factors = (3x - 1) (2x - 1)</h2><h2>values :- x = 1/3 , 1/2</h2>
Step-by-step explanation:
= > 6x^2 + 1 = 5x
• Bring it in the standard form,
= > 6x^2 - 5x + 1 = 0
= > 6x^2 - (3 + 2)x + 1 = 0
= > 6x^2 - 3x - 2x + 1 = 0
• Take out common
= > 3x (2x - 1) - 1 (2x - 1) = 0
= > (3x - 1) (2x - 1) = 0...factors
= > x = 1/3 and 1/2... values of x
<h2>Hope it helps you!! </h2>
The answer is A.
Ordered pairs that equate to a function would not have two separate points with the same x-value. In other words, every x-value must be associated with only one y-value.
Answer:
It’s b.
Step-by-step explanation:
To get the slope of the line, you need to points. Two points you already have are (0,0) and (-5,6). So all you need to do is plug those points into slope equation (y1-y2 over x1-x2) 0-6 over 0+5 equals -6/5. The slope equals -6/5, and when you plug it into y=mx+b it equals y=-6/5x. Which is b.