$\rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}$

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0

3 years ago

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What is the rate of change: y=x+5

const2013 [10]

Answer:

x or 1x.

Step-by-step explanation:

The rate of change is slope.

Slope=m

y=mx+b

y=<u>x</u>+5

x is the same thing as 1x. So...

4 0

3 years ago

A bag of 33 tulip bulbs contains 11 red tulips, 12 yellow tulips, and 10 purple tulips. Suppose two tulip bulbs are randomly sel

Harrizon [31]

The answer will be 35/132

7 0

3 years ago