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Ber [7]
2 years ago
15

There are 64 cookies in a jar. The probability of randomly choosing oatmeal cookies from the jar is 37.5%. How many of the cooki

es are oatmeal cookies
Mathematics
1 answer:
Rufina [12.5K]2 years ago
6 0

Answer:

the number of cookies that are oatmeal cookies is 24

Step-by-step explanation:

Given that

There are 64 cookies in a jar

And, the probability of randomly selecting the oatmeal cookies is 37.5%

We need to find out the number of cookies that are oatmeal cookies

So, the number of cookies that are oatmeal cookies are

= 64 cookies × 37.50%

= 24 cookies

hence, the number of cookies that are oatmeal cookies is 24

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Laurie is trying to stay within 10 feet of her current diving depth of -30 feet (with regard to sea level) so that the light is
frez [133]

Answer:

It should be the first one

Step-by-step explanation:

since positive ten would represent going further up and negative ten going further down, the diver would be within ten feet of her current position

8 0
3 years ago
PLEASE ANSWER THIS: look at the pic for question. Thanks!!!
Nadya [2.5K]

Answer:

\text{D. }b^2-4ac>0

Step-by-step explanation:

The equation b^2-4ac represents the discriminant of a quadratic. It is the part taken from under the radical in the quadratic formula.

For any quadratic:

  • If the discriminant is positive, or greater than 0, the quadratic has two solutions
  • If the discriminant is equal to 0, the quadratic has one distinct real solution (the solution is repeated).
  • If the discriminant is negative, or less than 0, the quadratic has zero solutions

In the graph, we see that the equation intersects the x-axis at two distinct points. Therefore, the quadratic has two solutions and the discriminant must be positive. Thus, we have b^2-4ac>0.

4 0
3 years ago
If x=9, what is the value of your in the equation below? y=8x-(1+4x)
Phantasy [73]
Y=72-(1+36)
Y=72-37
Y=35
5 0
3 years ago
Read 2 more answers
What is the solution to the equation 6t = 114
Tpy6a [65]
Divide the 114 by 6t to get an anwer

7 0
3 years ago
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A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.
Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

a)

The probability that the birth is a male can be written as

p(m) = 0.52 (which corresponds to 52%)

While the probability that the birth is a female can be written as

p(f) = 0.48 (which corresponds to 48%)

Here we want to calculate the probability that over  2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male  does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

p(mm)=p(m)\cdot p(m)

And substituting, we find

p(mm)=0.52\cdot 0.52 = 0.27

So, 27%.

b)

In this case, we want to find the probability that both children are female, so the probability

p(ff)

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

p(ff)=p(f)\cdot p(f)

And substituting

p(f)=0.48

We find:

p(ff)=0.48\cdot 0.48=0.23

Which means 23%.

c)

In this case, we want to find the probability they have exactly one male and exactly one female child. This is given by the sum of two probabilities:

- The probability that 1st child is a male and 2nd child is a female, namely p(mf)

- The probability that 1st child is a female and 2nd child is a male, namely p(fm)

So, this probability is

p(mf Ufm)=p(mf)+p(fm)

We have:

p(mf)=p(m)\cdot p(f)=0.52\cdot 0.48=0.25

p(fm)=p(f)\cdot p(m)=0.48\cdot 0.52=0.25

Therefore, this probability is

p(mfUfm)=0.25+0.25=0.50

So, 50%.

Learn more about probabilities:

brainly.com/question/5751004

brainly.com/question/6649771

brainly.com/question/8799684

brainly.com/question/7888686

#LearnwithBrainly

5 0
3 years ago
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