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2 years ago

Sum of two numbers = 14

Mathematics

1 answer:

Solnce55 [7]2 years ago

7 0

It is 10+4
Then 10x4
The difference is 6
So these are the numbers

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If town A had 35 people, 12 left, 13 joined, 39 joined, 25 got killed, how many people were there left?

Makovka662 [10]

Answer:

Step-by-step explanation:

35 - 12 + 13 + 39 - 25 = 50

6 0

3 years ago

Emily flipped a coin 30 times the coin landed heads up nine times and tails up 21 times

lara [203]

Part A)
The coin landed on heads 9 times out of 30 flips, so the experimental probability is 9/30, which reduces to 3/10 probability.

Part B)
Theoretically a coin has a 1/2 probability of landing on heads each flip

8 0

3 years ago

Given that point A is the midpoint of line segment ED, where E( -1,9) and A(4,5), what is the location of point D?

yuradex [85]

Answer:

D(9, 1)

Step-by-step explanation:

A being the midpoint means its coordinates satisfy ...

A = (E + D)/2

Solving for D, we find ...

D = 2A -E

= 2(4, 5) -(-1, 9) = (2·4 +1, 2·5 -9)

D = (9, 1)

8 0

3 years ago

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

8 0

3 years ago

Donnell and Maria are both members of a populationand a simple random sample is being conducted. If the chance of Donnell being

harina [27]

Answer:

289/290

Step-by-step explanation:

Given that the chance of Donnell being selected is 1/290

then P( Donnell being selected )= 1/290

Since Donnell and Maria are both member of a population.

from probability theorem which gives the likely hood of an event to happen which cannot be more than 1, then the probability of Donnell and Maria to be selected is 1

P(Donnell and Maria)= 1

But the chance of Donnell being selected is 1/290

Then,

1/290 + P(Maria)= 1

P(Maria)= 1-(1/290)

= 289/290

the chance of Maria being selected is 289/290

4 0

3 years ago